Inputs
m
kPa
kPa
kPa
m²/year
years
e.g. 0.9 for 90%
Method & assumptions
- NC clay (σ'0 + Δσ ≤ σ'p never): S = (Cc·H)/(1+e₀)·log((σ'0+Δσ)/σ'0).
- OC clay, no exceedance (σ'0+Δσ ≤ σ'p): S = (Cr·H)/(1+e₀)·log((σ'0+Δσ)/σ'0).
- OC with exceedance: S = (Cr·H)/(1+e₀)·log(σ'p/σ'0) + (Cc·H)/(1+e₀)·log((σ'0+Δσ)/σ'p).
- Time factor Tv = Cv·t/Hdr²; Hdr = H/2 (double drainage) or H (single).
- U(Tv) approx: U = √(4Tv/π) for U≤60%, else U = 1 − 10^{(1.781 − 0.933·log(100·(1−U)))} simplified to: Tv = 1.781 − 0.933·log(100·(1−U)) when U>60%.
Results
Stress Path—
σ'0 + Δσ—
Primary Settlement S—
Hdr—
Tv at t—
Degree of Consolidation U(t)—
Settlement at t—
Time for U = target—
Settlement vs Time
| U% | Tv | Time (yr) | S(t) (mm) |
|---|