Input
Gross area in shear.
Net area in shear.
Net area in tension.
1.0 uniform tens., 0.5 non-uniform.
Results
Term 1 = 0.6 Fu Anv + Ubs Fu Ant—
Term 2 = 0.6 Fy Agv + Ubs Fu Ant—
Rn = min(T1, T2)—
ϕ Rn (ϕ=0.75)—
DCR = Pu / ϕ Rn—
Method
AISC 360 §J4.3 — Block-shear rupture: Rn = min[0.6·Fu·Anv + Ubs·Fu·Ant, 0.6·Fy·Agv + Ubs·Fu·Ant]. Ubs = 1.0 for uniform tension stress; 0.5 for non-uniform (e.g., coped beams). ϕ = 0.75 (LRFD).